Base | Representation |
---|---|
bin | 1111011101100010010… |
… | …10101101011011101101 |
3 | 1212210020221220111120111 |
4 | 13232301022231123231 |
5 | 32201001324232143 |
6 | 1044015431020021 |
7 | 53244644662225 |
oct | 7566112553355 |
9 | 1783227814514 |
10 | 531253352173 |
11 | 195337738575 |
12 | 86b6380a611 |
13 | 3b13509747b |
14 | 1b9d9cc9085 |
15 | dc447d599d |
hex | 7bb12ad6ed |
531253352173 has 2 divisors, whose sum is σ = 531253352174. Its totient is φ = 531253352172.
The previous prime is 531253352087. The next prime is 531253352177. The reversal of 531253352173 is 371253352135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 491116435209 + 40136916964 = 700797^2 + 200342^2 .
It is a cyclic number.
It is not a de Polignac number, because 531253352173 - 213 = 531253343981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (531253352177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265626676086 + 265626676087.
It is an arithmetic number, because the mean of its divisors is an integer number (265626676087).
Almost surely, 2531253352173 is an apocalyptic number.
It is an amenable number.
531253352173 is a deficient number, since it is larger than the sum of its proper divisors (1).
531253352173 is an equidigital number, since it uses as much as digits as its factorization.
531253352173 is an evil number, because the sum of its binary digits is even.
The product of its digits is 283500, while the sum is 40.
The spelling of 531253352173 in words is "five hundred thirty-one billion, two hundred fifty-three million, three hundred fifty-two thousand, one hundred seventy-three".
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