Base | Representation |
---|---|
bin | 100110101010000100000… |
… | …1100110010101101001100 |
3 | 200210220210221122011001122 |
4 | 1031110020030302231030 |
5 | 1144022022100210200 |
6 | 15144433012300112 |
7 | 1055565251564600 |
oct | 115241014625514 |
9 | 20726727564048 |
10 | 5313012116300 |
11 | 1769265914389 |
12 | 719845011638 |
13 | 2c7026947775 |
14 | 145218ac9500 |
15 | 9330c427385 |
hex | 4d508332b4c |
5313012116300 has 54 divisors (see below), whose sum is σ = 13411560597372. Its totient is φ = 1821604152480.
The previous prime is 5313012116221. The next prime is 5313012116303. The reversal of 5313012116300 is 36112103135.
It is a self number, because there is not a number n which added to its sum of digits gives 5313012116300.
It is not an unprimeable number, because it can be changed into a prime (5313012116303) by changing a digit.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 542139194 + ... + 542148993.
Almost surely, 25313012116300 is an apocalyptic number.
5313012116300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
5313012116300 is an abundant number, since it is smaller than the sum of its proper divisors (8098548481072).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5313012116300 is a wasteful number, since it uses less digits than its factorization.
5313012116300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1084288215 (or 1084288201 counting only the distinct ones).
The product of its (nonzero) digits is 1620, while the sum is 26.
Adding to 5313012116300 its reverse (36112103135), we get a palindrome (5349124219435).
The spelling of 5313012116300 in words is "five trillion, three hundred thirteen billion, twelve million, one hundred sixteen thousand, three hundred".
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