Base | Representation |
---|---|
bin | 1111011101101000000… |
… | …10000101111111001101 |
3 | 1212210101022100212020022 |
4 | 13232310002011333031 |
5 | 32201101131100401 |
6 | 1044024305231525 |
7 | 53246100412436 |
oct | 7566402057715 |
9 | 1783338325208 |
10 | 531301425101 |
11 | 195361892467 |
12 | 86b779325a5 |
13 | 3b1420296a5 |
14 | 1ba0244048d |
15 | dc48b2e71b |
hex | 7bb4085fcd |
531301425101 has 2 divisors, whose sum is σ = 531301425102. Its totient is φ = 531301425100.
The previous prime is 531301425079. The next prime is 531301425107. The reversal of 531301425101 is 101524103135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 531293752201 + 7672900 = 728899^2 + 2770^2 .
It is a cyclic number.
It is not a de Polignac number, because 531301425101 - 210 = 531301424077 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (531301425107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265650712550 + 265650712551.
It is an arithmetic number, because the mean of its divisors is an integer number (265650712551).
Almost surely, 2531301425101 is an apocalyptic number.
It is an amenable number.
531301425101 is a deficient number, since it is larger than the sum of its proper divisors (1).
531301425101 is an equidigital number, since it uses as much as digits as its factorization.
531301425101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 26.
Adding to 531301425101 its reverse (101524103135), we get a palindrome (632825528236).
The spelling of 531301425101 in words is "five hundred thirty-one billion, three hundred one million, four hundred twenty-five thousand, one hundred one".
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