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53130300170000 = 24541371671811283
BaseRepresentation
bin11000001010010010111001…
…01010110001111100010000
320222010012120222012000001012
430011021130222301330100
523430441323320420000
6304555420053430052
714122352240020604
oct1405113452617420
9228105528160035
1053130300170000
1115a24485384079
125b6101203b328
132385220384991
14d1973d7c5504
1562209375b735
hex30525cab1f10

53130300170000 has 400 divisors, whose sum is σ = 131170902774912. Its totient is φ = 20838551040000.

The previous prime is 53130300169981. The next prime is 53130300170047. The reversal of 53130300170000 is 7100303135.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (400).

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 41410989359 + ... + 41410990641.

Almost surely, 253130300170000 is an apocalyptic number.

53130300170000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 53130300170000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (65585451387456).

53130300170000 is an abundant number, since it is smaller than the sum of its proper divisors (78040602604912).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53130300170000 is a wasteful number, since it uses less digits than its factorization.

53130300170000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1796 (or 1775 counting only the distinct ones).

The product of its (nonzero) digits is 945, while the sum is 23.

Adding to 53130300170000 its reverse (7100303135), we get a palindrome (53137400473135).

The spelling of 53130300170000 in words is "fifty-three trillion, one hundred thirty billion, three hundred million, one hundred seventy thousand".