Base | Representation |
---|---|
bin | 11000001010010010111101… |
… | …01001101101000111101110 |
3 | 20222010012200021210102101120 |
4 | 30011021132221231013232 |
5 | 23430441410330130132 |
6 | 304555423242521410 |
7 | 14122353122566236 |
oct | 1405113651550756 |
9 | 228105607712346 |
10 | 53130333442542 |
11 | 15a244a213a244 |
12 | 5b61021206266 |
13 | 2385227234385 |
14 | d19743da6cc6 |
15 | 62209663002c |
hex | 30525ea6d1ee |
53130333442542 has 64 divisors (see below), whose sum is σ = 107025469931520. Its totient is φ = 17583129023456.
The previous prime is 53130333442531. The next prime is 53130333442619. The reversal of 53130333442542 is 24524433303135.
It is a junction number, because it is equal to n+sod(n) for n = 53130333442494 and 53130333442503.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 970088443 + ... + 970143209.
It is an arithmetic number, because the mean of its divisors is an integer number (1672272967680).
Almost surely, 253130333442542 is an apocalyptic number.
53130333442542 is an abundant number, since it is smaller than the sum of its proper divisors (53895136488978).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53130333442542 is a wasteful number, since it uses less digits than its factorization.
53130333442542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56965.
The product of its (nonzero) digits is 1555200, while the sum is 42.
Adding to 53130333442542 its reverse (24524433303135), we get a palindrome (77654766745677).
The spelling of 53130333442542 in words is "fifty-three trillion, one hundred thirty billion, three hundred thirty-three million, four hundred forty-two thousand, five hundred forty-two".
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