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5313140524121 is a prime number
BaseRepresentation
bin100110101010000111111…
…0110101000010001011001
3200210221010220020221110212
41031110033312220101121
51144022302433232441
615144453440420505
71055601401204453
oct115241766502131
920727126227425
105313140524121
111769321349051
12719880017735
132c7047426621
1414522bb932d3
159331883deeb
hex4d50fda8459

5313140524121 has 2 divisors, whose sum is σ = 5313140524122. Its totient is φ = 5313140524120.

The previous prime is 5313140524117. The next prime is 5313140524169. The reversal of 5313140524121 is 1214250413135.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3287201068096 + 2025939456025 = 1813064^2 + 1423355^2 .

It is a cyclic number.

It is not a de Polignac number, because 5313140524121 - 22 = 5313140524117 is a prime.

It is not a weakly prime, because it can be changed into another prime (5313140574121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2656570262060 + 2656570262061.

It is an arithmetic number, because the mean of its divisors is an integer number (2656570262061).

Almost surely, 25313140524121 is an apocalyptic number.

It is an amenable number.

5313140524121 is a deficient number, since it is larger than the sum of its proper divisors (1).

5313140524121 is an equidigital number, since it uses as much as digits as its factorization.

5313140524121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 5313140524121 its reverse (1214250413135), we get a palindrome (6527390937256).

The spelling of 5313140524121 in words is "five trillion, three hundred thirteen billion, one hundred forty million, five hundred twenty-four thousand, one hundred twenty-one".