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53132435040000 = 28354110692573
BaseRepresentation
bin11000001010010110110111…
…11010101010011100000000
320222010102002202022122010110
430011023123322222130000
523431010211332240000
6305000411555231320
714122456162065441
oct1405133372523400
9228112082278113
1053132435040000
1115a25380469548
125b61508ba8540
1323854a0761374
14d198a314b2c8
1562216adb0850
hex3052dbeaa700

53132435040000 has 180 divisors, whose sum is σ = 176705640200936. Its totient is φ = 14168649216000.

The previous prime is 53132435039933. The next prime is 53132435040109. The reversal of 53132435040000 is 4053423135.

It is a super-3 number, since 3×531324350400003 (a number of 42 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a self number, because there is not a number n which added to its sum of digits gives 53132435040000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 54866287 + ... + 55826286.

Almost surely, 253132435040000 is an apocalyptic number.

53132435040000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

53132435040000 is an abundant number, since it is smaller than the sum of its proper divisors (123573205160936).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53132435040000 is an equidigital number, since it uses as much as digits as its factorization.

53132435040000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110692612 (or 110692583 counting only the distinct ones).

The product of its (nonzero) digits is 21600, while the sum is 30.

Adding to 53132435040000 its reverse (4053423135), we get a palindrome (53136488463135).

The spelling of 53132435040000 in words is "fifty-three trillion, one hundred thirty-two billion, four hundred thirty-five million, forty thousand".