Base | Representation |
---|---|
bin | 100110101010001011110… |
… | …1000100100111011011111 |
3 | 200210221110222212202111021 |
4 | 1031110113220210323133 |
5 | 1144023034342330033 |
6 | 15144514422305011 |
7 | 1055604544551226 |
oct | 115242750447337 |
9 | 20727428782437 |
10 | 5313271058143 |
11 | 1769388aa5204 |
12 | 7198b7888167 |
13 | 2c706849b1a9 |
14 | 145241251cbd |
15 | 93325025b2d |
hex | 4d517a24edf |
5313271058143 has 2 divisors, whose sum is σ = 5313271058144. Its totient is φ = 5313271058142.
The previous prime is 5313271058071. The next prime is 5313271058149. The reversal of 5313271058143 is 3418501723135.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5313271058143 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5313271058143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5313271058149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2656635529071 + 2656635529072.
It is an arithmetic number, because the mean of its divisors is an integer number (2656635529072).
Almost surely, 25313271058143 is an apocalyptic number.
5313271058143 is a deficient number, since it is larger than the sum of its proper divisors (1).
5313271058143 is an equidigital number, since it uses as much as digits as its factorization.
5313271058143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 302400, while the sum is 43.
The spelling of 5313271058143 in words is "five trillion, three hundred thirteen billion, two hundred seventy-one million, fifty-eight thousand, one hundred forty-three".
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