Base | Representation |
---|---|
bin | 11000001010011000000000… |
… | …01101110010011001101111 |
3 | 20222010110200012020200122202 |
4 | 30011030000031302121233 |
5 | 23431012433233030020 |
6 | 305000552232132115 |
7 | 14122510235331563 |
oct | 1405140015623157 |
9 | 228113605220582 |
10 | 53133044033135 |
11 | 15a256631aa060 |
12 | 5b61658b3703b |
13 | 2385569988431 |
14 | d1991dd956a3 |
15 | 6221a45a7e75 |
hex | 30530037266f |
53133044033135 has 32 divisors (see below), whose sum is σ = 69734938001472. Its totient is φ = 38542805959680.
The previous prime is 53133044033093. The next prime is 53133044033183.
53133044033135 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53133044033135 - 28 = 53133044032879 is a prime.
It is a super-3 number, since 3×531330440331353 (a number of 42 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 490207067 + ... + 490315443.
It is an arithmetic number, because the mean of its divisors is an integer number (2179216812546).
Almost surely, 253133044033135 is an apocalyptic number.
53133044033135 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53133044033135 is a deficient number, since it is larger than the sum of its proper divisors (16601893968337).
53133044033135 is a wasteful number, since it uses less digits than its factorization.
53133044033135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 131243.
The product of its (nonzero) digits is 291600, while the sum is 38.
It can be divided in two parts, 5313304 and 4033135, that added together give a palindrome (9346439).
The spelling of 53133044033135 in words is "fifty-three trillion, one hundred thirty-three billion, forty-four million, thirty-three thousand, one hundred thirty-five".
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