Base | Representation |
---|---|
bin | 100110101010001101111… |
… | …1011101010000011011101 |
3 | 200210221200000120100121212 |
4 | 1031110123323222003131 |
5 | 1144023211322344413 |
6 | 15144525520034205 |
7 | 1055606411515205 |
oct | 115243373520335 |
9 | 20727600510555 |
10 | 5313343168733 |
11 | 1769415777a36 |
12 | 719917a62965 |
13 | 2c707a3c8592 |
14 | 14524aa63405 |
15 | 9332b51bca8 |
hex | 4d51beea0dd |
5313343168733 has 2 divisors, whose sum is σ = 5313343168734. Its totient is φ = 5313343168732.
The previous prime is 5313343168711. The next prime is 5313343168781. The reversal of 5313343168733 is 3378613433135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2877864566329 + 2435478602404 = 1696427^2 + 1560602^2 .
It is a cyclic number.
It is not a de Polignac number, because 5313343168733 - 28 = 5313343168477 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5313340168733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2656671584366 + 2656671584367.
It is an arithmetic number, because the mean of its divisors is an integer number (2656671584367).
Almost surely, 25313343168733 is an apocalyptic number.
It is an amenable number.
5313343168733 is a deficient number, since it is larger than the sum of its proper divisors (1).
5313343168733 is an equidigital number, since it uses as much as digits as its factorization.
5313343168733 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4898880, while the sum is 50.
The spelling of 5313343168733 in words is "five trillion, three hundred thirteen billion, three hundred forty-three million, one hundred sixty-eight thousand, seven hundred thirty-three".
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