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53134030 = 255313403
BaseRepresentation
bin1100101010110…
…0001011001110
310200222111012001
43022230023032
5102100242110
65134502514
71213426465
oct312541316
9120874161
1053134030
1127aa1424
1215964a3a
13b014a71
1470b19dc
1549e863a
hex32ac2ce

53134030 has 8 divisors (see below), whose sum is σ = 95641272. Its totient is φ = 21253608.

The previous prime is 53134021. The next prime is 53134063. The reversal of 53134030 is 3043135.

53134030 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 53133989 and 53134007.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2656692 + ... + 2656711.

It is an arithmetic number, because the mean of its divisors is an integer number (11955159).

Almost surely, 253134030 is an apocalyptic number.

53134030 is a deficient number, since it is larger than the sum of its proper divisors (42507242).

53134030 is a wasteful number, since it uses less digits than its factorization.

53134030 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5313410.

The product of its (nonzero) digits is 540, while the sum is 19.

The square root of 53134030 is about 7289.3092951253. The cubic root of 53134030 is about 375.9449472363.

Adding to 53134030 its reverse (3043135), we get a palindrome (56177165).

The spelling of 53134030 in words is "fifty-three million, one hundred thirty-four thousand, thirty".

Divisors: 1 2 5 10 5313403 10626806 26567015 53134030