Base | Representation |
---|---|
bin | 1001111001011010… |
… | …00001101001011011 |
3 | 111201022002212022121 |
4 | 10330231001221123 |
5 | 41340212402413 |
6 | 2235124402111 |
7 | 245446120153 |
oct | 47455015133 |
9 | 14638085277 |
10 | 5313403483 |
11 | 2287306753 |
12 | 1043546337 |
13 | 668a7043b |
14 | 385963763 |
15 | 211711b8d |
hex | 13cb41a5b |
5313403483 has 2 divisors, whose sum is σ = 5313403484. Its totient is φ = 5313403482.
The previous prime is 5313403471. The next prime is 5313403493. The reversal of 5313403483 is 3843043135.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5313403483 - 29 = 5313402971 is a prime.
It is not a weakly prime, because it can be changed into another prime (5313403493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2656701741 + 2656701742.
It is an arithmetic number, because the mean of its divisors is an integer number (2656701742).
Almost surely, 25313403483 is an apocalyptic number.
5313403483 is a deficient number, since it is larger than the sum of its proper divisors (1).
5313403483 is an equidigital number, since it uses as much as digits as its factorization.
5313403483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 34.
The square root of 5313403483 is about 72893.0962643240. The cubic root of 5313403483 is about 1744.9819220192.
The spelling of 5313403483 in words is "five billion, three hundred thirteen million, four hundred three thousand, four hundred eighty-three".
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