Base | Representation |
---|---|
bin | 110001011111000011… |
… | …110011101010010000 |
3 | 12002011000211021111010 |
4 | 301133003303222100 |
5 | 1332304404103404 |
6 | 40224251250520 |
7 | 3560502204003 |
oct | 613703635220 |
9 | 162130737433 |
10 | 53134441104 |
11 | 20597009048 |
12 | a36a749a40 |
13 | 501a2662c4 |
14 | 2800b3153a |
15 | 15aeb43189 |
hex | c5f0f3a90 |
53134441104 has 20 divisors (see below), whose sum is σ = 137263972976. Its totient is φ = 17711480352.
The previous prime is 53134441079. The next prime is 53134441117. The reversal of 53134441104 is 40114443135.
53134441104 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×531344411043 (a number of 33 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 553483714 + ... + 553483809.
Almost surely, 253134441104 is an apocalyptic number.
It is an amenable number.
53134441104 is an abundant number, since it is smaller than the sum of its proper divisors (84129531872).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53134441104 is a wasteful number, since it uses less digits than its factorization.
53134441104 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1106967534 (or 1106967528 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 53134441104 its reverse (40114443135), we get a palindrome (93248884239).
The spelling of 53134441104 in words is "fifty-three billion, one hundred thirty-four million, four hundred forty-one thousand, one hundred four".
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