53135304244081 has 2 divisors, whose sum is σ = 53135304244082. Its totient is φ = 53135304244080.

The previous prime is 53135304244049. The next prime is 53135304244097. The reversal of 53135304244081 is 18044240353135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43164361261681 + 9970942982400 = 6569959^2 + 3157680^2 .

It is a cyclic number.

It is not a de Polignac number, because 53135304244081 - 2⁵ = 53135304244049 is a prime.

It is a super-2 number, since 2×53135304244081² (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (53135304242081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26567652122040 + 26567652122041.

It is an arithmetic number, because the mean of its divisors is an integer number (26567652122041).

Almost surely, 2^{53135304244081} is an apocalyptic number.

It is an amenable number.

53135304244081 is a deficient number, since it is larger than the sum of its proper divisors (1).

53135304244081 is an equidigital number, since it uses as much as digits as its factorization.

53135304244081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 691200, while the sum is 43.

The spelling of 53135304244081 in words is "fifty-three trillion, one hundred thirty-five billion, three hundred four million, two hundred forty-four thousand, eighty-one".