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53135304244049 is a prime number
BaseRepresentation
bin11000001010011100001101…
…11011110011101101010001
320222010200111201020022011002
430011032012323303231101
523431032100341302144
6305002004412231345
714122620241654016
oct1405160673635521
9228120451208132
1053135304244049
1115a26613013a65
125b61b89a6b555
13238583a00ba41
14d19a9622770d
15622287c1a14e
hex305386ef3b51

53135304244049 has 2 divisors, whose sum is σ = 53135304244050. Its totient is φ = 53135304244048.

The previous prime is 53135304243991. The next prime is 53135304244081. The reversal of 53135304244049 is 94044240353135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39077251392400 + 14058052851649 = 6251180^2 + 3749407^2 .

It is a cyclic number.

It is not a de Polignac number, because 53135304244049 - 240 = 52035792616273 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53135304243994 and 53135304244012.

It is not a weakly prime, because it can be changed into another prime (53135304214049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26567652122024 + 26567652122025.

It is an arithmetic number, because the mean of its divisors is an integer number (26567652122025).

Almost surely, 253135304244049 is an apocalyptic number.

It is an amenable number.

53135304244049 is a deficient number, since it is larger than the sum of its proper divisors (1).

53135304244049 is an equidigital number, since it uses as much as digits as its factorization.

53135304244049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3110400, while the sum is 47.

The spelling of 53135304244049 in words is "fifty-three trillion, one hundred thirty-five billion, three hundred four million, two hundred forty-four thousand, forty-nine".