Base | Representation |
---|---|
bin | 11000001010011100001101… |
… | …11011110011101101010001 |
3 | 20222010200111201020022011002 |
4 | 30011032012323303231101 |
5 | 23431032100341302144 |
6 | 305002004412231345 |
7 | 14122620241654016 |
oct | 1405160673635521 |
9 | 228120451208132 |
10 | 53135304244049 |
11 | 15a26613013a65 |
12 | 5b61b89a6b555 |
13 | 238583a00ba41 |
14 | d19a9622770d |
15 | 622287c1a14e |
hex | 305386ef3b51 |
53135304244049 has 2 divisors, whose sum is σ = 53135304244050. Its totient is φ = 53135304244048.
The previous prime is 53135304243991. The next prime is 53135304244081. The reversal of 53135304244049 is 94044240353135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 39077251392400 + 14058052851649 = 6251180^2 + 3749407^2 .
It is a cyclic number.
It is not a de Polignac number, because 53135304244049 - 240 = 52035792616273 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53135304243994 and 53135304244012.
It is not a weakly prime, because it can be changed into another prime (53135304214049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26567652122024 + 26567652122025.
It is an arithmetic number, because the mean of its divisors is an integer number (26567652122025).
Almost surely, 253135304244049 is an apocalyptic number.
It is an amenable number.
53135304244049 is a deficient number, since it is larger than the sum of its proper divisors (1).
53135304244049 is an equidigital number, since it uses as much as digits as its factorization.
53135304244049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3110400, while the sum is 47.
The spelling of 53135304244049 in words is "fifty-three trillion, one hundred thirty-five billion, three hundred four million, two hundred forty-four thousand, forty-nine".
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