Base | Representation |
---|---|
bin | 100110101010010101010… |
… | …1010110011111101101111 |
3 | 200210222022020210120102021 |
4 | 1031110222222303331233 |
5 | 1144024213121123434 |
6 | 15145010231211011 |
7 | 1055615503163404 |
oct | 115245252637557 |
9 | 20728266716367 |
10 | 5313590411119 |
11 | 1769532297891 |
12 | 719986816a67 |
13 | 2c70b96b3a53 |
14 | 1452718222ab |
15 | 933430a8cb4 |
hex | 4d52aab3f6f |
5313590411119 has 2 divisors, whose sum is σ = 5313590411120. Its totient is φ = 5313590411118.
The previous prime is 5313590411113. The next prime is 5313590411131. The reversal of 5313590411119 is 9111140953135.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5313590411119 - 23 = 5313590411111 is a prime.
It is a super-2 number, since 2×53135904111192 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5313590411111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2656795205559 + 2656795205560.
It is an arithmetic number, because the mean of its divisors is an integer number (2656795205560).
Almost surely, 25313590411119 is an apocalyptic number.
5313590411119 is a deficient number, since it is larger than the sum of its proper divisors (1).
5313590411119 is an equidigital number, since it uses as much as digits as its factorization.
5313590411119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72900, while the sum is 43.
The spelling of 5313590411119 in words is "five trillion, three hundred thirteen billion, five hundred ninety million, four hundred eleven thousand, one hundred nineteen".
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