Base | Representation |
---|---|
bin | 1111011101110011110… |
… | …11000101001110111101 |
3 | 1212210122012022200220220 |
4 | 13232321323011032331 |
5 | 32201301431002201 |
6 | 1044042155331553 |
7 | 53251410412524 |
oct | 7567173051675 |
9 | 1783565280826 |
10 | 531400250301 |
11 | 195402651288 |
12 | 86ba4a50bb9 |
13 | 3b15964b53b |
14 | 1ba116074bb |
15 | dc52651036 |
hex | 7bb9ec53bd |
531400250301 has 16 divisors (see below), whose sum is σ = 764367067584. Its totient is φ = 327136519424.
The previous prime is 531400250287. The next prime is 531400250321. The reversal of 531400250301 is 103052004135.
It is not a de Polignac number, because 531400250301 - 215 = 531400217533 is a prime.
It is a super-3 number, since 3×5314002503013 (a number of 36 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (531400250321) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 98295531 + ... + 98300936.
It is an arithmetic number, because the mean of its divisors is an integer number (47772941724).
Almost surely, 2531400250301 is an apocalyptic number.
531400250301 is a gapful number since it is divisible by the number (51) formed by its first and last digit.
It is an amenable number.
531400250301 is a deficient number, since it is larger than the sum of its proper divisors (232966817283).
531400250301 is a wasteful number, since it uses less digits than its factorization.
531400250301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 196596540.
The product of its (nonzero) digits is 1800, while the sum is 24.
Adding to 531400250301 its reverse (103052004135), we get a palindrome (634452254436).
The spelling of 531400250301 in words is "five hundred thirty-one billion, four hundred million, two hundred fifty thousand, three hundred one".
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