Base | Representation |
---|---|
bin | 11000001010100101010000… |
… | …11111010001001100001101 |
3 | 20222011011001021020202120011 |
4 | 30011102220133101030031 |
5 | 23431122023002432102 |
6 | 305004130430153221 |
7 | 14123151520351351 |
oct | 1405225037211415 |
9 | 228134037222504 |
10 | 53140162155277 |
11 | 15a286861a262a |
12 | 5b62b04952811 |
13 | 23861325ab622 |
14 | d19dd749d461 |
15 | 62246e4562d7 |
hex | 3054a87d130d |
53140162155277 has 2 divisors, whose sum is σ = 53140162155278. Its totient is φ = 53140162155276.
The previous prime is 53140162155253. The next prime is 53140162155317. The reversal of 53140162155277 is 77255126104135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 38647682159076 + 14492479996201 = 6216726^2 + 3806899^2 .
It is a cyclic number.
It is not a de Polignac number, because 53140162155277 - 243 = 44344069133069 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53140162155277.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53140162155077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26570081077638 + 26570081077639.
It is an arithmetic number, because the mean of its divisors is an integer number (26570081077639).
Almost surely, 253140162155277 is an apocalyptic number.
It is an amenable number.
53140162155277 is a deficient number, since it is larger than the sum of its proper divisors (1).
53140162155277 is an equidigital number, since it uses as much as digits as its factorization.
53140162155277 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1764000, while the sum is 49.
The spelling of 53140162155277 in words is "fifty-three trillion, one hundred forty billion, one hundred sixty-two million, one hundred fifty-five thousand, two hundred seventy-seven".
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