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53141100154000 = 2453411374730381
BaseRepresentation
bin11000001010100111000000…
…11001011100110010010000
320222011020110122021000220121
430011103200121130302100
523431130433114412000
6305004403454520024
714123214000251455
oct1405234031346220
9228136418230817
1053141100154000
1115a29017718991
125b63126b06014
132386251a1a961
14d1a085cab82c
156224c698bb1a
hex3054e065cc90

53141100154000 has 160 divisors (see below), whose sum is σ = 132590034132192. Its totient is φ = 20586613760000.

The previous prime is 53141100153997. The next prime is 53141100154003. The reversal of 53141100154000 is 45100114135.

It is an interprime number because it is at equal distance from previous prime (53141100153997) and next prime (53141100154003).

It can be written as a sum of positive squares in 16 ways, for example, as 49837895683216 + 3303204470784 = 7059596^2 + 1817472^2 .

It is a Harshad number since it is a multiple of its sum of digits (25).

It is not an unprimeable number, because it can be changed into a prime (53141100154003) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8868810 + ... + 13599190.

Almost surely, 253141100154000 is an apocalyptic number.

53141100154000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 53141100154000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (66295017066096).

53141100154000 is an abundant number, since it is smaller than the sum of its proper divisors (79448933978192).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53141100154000 is a wasteful number, since it uses less digits than its factorization.

53141100154000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4730582 (or 4730566 counting only the distinct ones).

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 53141100154000 its reverse (45100114135), we get a palindrome (53186200268135).

The spelling of 53141100154000 in words is "fifty-three trillion, one hundred forty-one billion, one hundred million, one hundred fifty-four thousand".

Divisors: 1 2 4 5 8 10 16 20 25 40 41 50 80 82 100 125 137 164 200 205 250 274 328 400 410 500 548 656 685 820 1000 1025 1096 1370 1640 2000 2050 2192 2740 3280 3425 4100 5125 5480 5617 6850 8200 10250 10960 11234 13700 16400 17125 20500 22468 27400 28085 34250 41000 44936 54800 56170 68500 82000 89872 112340 137000 140425 224680 274000 280850 449360 561700 702125 1123400 1404250 2246800 2808500 4730381 5617000 9460762 11234000 18921524 23651905 37843048 47303810 75686096 94607620 118259525 189215240 193945621 236519050 378430480 387891242 473038100 591297625 648062197 775782484 946076200 969728105 1182595250 1296124394 1551564968 1892152400 1939456210 2365190500 2592248788 3103129936 3240310985 3878912420 4730381000 4848640525 5184497576 6480621970 7757824840 9460762000 9697281050 10368995152 12961243940 15515649680 16201554925 19394562100 24243202625 25922487880 26570550077 32403109850 38789124200 48486405250 51844975760 53141100154 64806219700 77578248400 81007774625 96972810500 106282200308 129612439400 132852750385 162015549250 193945621000 212564400616 259224878800 265705500770 324031098500 387891242000 425128801232 531411001540 648062197000 664263751925 1062822003080 1296124394000 1328527503850 2125644006160 2657055007700 3321318759625 5314110015400 6642637519250 10628220030800 13285275038500 26570550077000 53141100154000