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53141510500349 is a prime number
BaseRepresentation
bin11000001010100111110001…
…10110110010111111111101
320222011021112020101210021112
430011103320312302333331
523431132303142002344
6305004512314011405
714123230112164505
oct1405237066627775
9228137466353245
1053141510500349
1115a292083101a7
125b63220416b65
1323862b8a4264b
14d1a0c45a6a05
156224ec9e5c9e
hex3054f8db2ffd

53141510500349 has 2 divisors, whose sum is σ = 53141510500350. Its totient is φ = 53141510500348.

The previous prime is 53141510500343. The next prime is 53141510500363. The reversal of 53141510500349 is 94300501514135.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31916646868324 + 21224863632025 = 5649482^2 + 4607045^2 .

It is a cyclic number.

It is not a de Polignac number, because 53141510500349 - 216 = 53141510434813 is a prime.

It is a super-3 number, since 3×531415105003493 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53141510500343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26570755250174 + 26570755250175.

It is an arithmetic number, because the mean of its divisors is an integer number (26570755250175).

Almost surely, 253141510500349 is an apocalyptic number.

It is an amenable number.

53141510500349 is a deficient number, since it is larger than the sum of its proper divisors (1).

53141510500349 is an equidigital number, since it uses as much as digits as its factorization.

53141510500349 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162000, while the sum is 41.

The spelling of 53141510500349 in words is "fifty-three trillion, one hundred forty-one billion, five hundred ten million, five hundred thousand, three hundred forty-nine".