Base | Representation |
---|---|
bin | 11000001010100111110001… |
… | …10110110010111111111101 |
3 | 20222011021112020101210021112 |
4 | 30011103320312302333331 |
5 | 23431132303142002344 |
6 | 305004512314011405 |
7 | 14123230112164505 |
oct | 1405237066627775 |
9 | 228137466353245 |
10 | 53141510500349 |
11 | 15a292083101a7 |
12 | 5b63220416b65 |
13 | 23862b8a4264b |
14 | d1a0c45a6a05 |
15 | 6224ec9e5c9e |
hex | 3054f8db2ffd |
53141510500349 has 2 divisors, whose sum is σ = 53141510500350. Its totient is φ = 53141510500348.
The previous prime is 53141510500343. The next prime is 53141510500363. The reversal of 53141510500349 is 94300501514135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 31916646868324 + 21224863632025 = 5649482^2 + 4607045^2 .
It is a cyclic number.
It is not a de Polignac number, because 53141510500349 - 216 = 53141510434813 is a prime.
It is a super-3 number, since 3×531415105003493 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53141510500343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26570755250174 + 26570755250175.
It is an arithmetic number, because the mean of its divisors is an integer number (26570755250175).
Almost surely, 253141510500349 is an apocalyptic number.
It is an amenable number.
53141510500349 is a deficient number, since it is larger than the sum of its proper divisors (1).
53141510500349 is an equidigital number, since it uses as much as digits as its factorization.
53141510500349 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 41.
The spelling of 53141510500349 in words is "fifty-three trillion, one hundred forty-one billion, five hundred ten million, five hundred thousand, three hundred forty-nine".
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