Base | Representation |
---|---|
bin | 1111011101110110110… |
… | …11011010110011010111 |
3 | 1212210200221211202010112 |
4 | 13232323123122303113 |
5 | 32201324412120341 |
6 | 1044044500513235 |
7 | 53252135154041 |
oct | 7567333326327 |
9 | 1783627752115 |
10 | 531425504471 |
11 | 1954159300a4 |
12 | 86bb13ab81b |
13 | 3b161951334 |
14 | 1ba14adca91 |
15 | dc5498daeb |
hex | 7bbb6dacd7 |
531425504471 has 2 divisors, whose sum is σ = 531425504472. Its totient is φ = 531425504470.
The previous prime is 531425504411. The next prime is 531425504503. The reversal of 531425504471 is 174405524135.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-531425504471 is a prime.
It is a super-3 number, since 3×5314255044713 (a number of 36 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (531425504411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265712752235 + 265712752236.
It is an arithmetic number, because the mean of its divisors is an integer number (265712752236).
Almost surely, 2531425504471 is an apocalyptic number.
531425504471 is a deficient number, since it is larger than the sum of its proper divisors (1).
531425504471 is an equidigital number, since it uses as much as digits as its factorization.
531425504471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 336000, while the sum is 41.
The spelling of 531425504471 in words is "five hundred thirty-one billion, four hundred twenty-five million, five hundred four thousand, four hundred seventy-one".
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