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53143131101 is a prime number
BaseRepresentation
bin110001011111100100…
…111101001111011101
312002011122011202220212
4301133210331033131
51332314120143401
640225201422205
73560636106164
oct613744751735
9162148152825
1053143131101
11205a0a03a65
12a37163a965
13501bcb9808
142801d543db
1515b07acdbb
hexc5f93d3dd

53143131101 has 2 divisors, whose sum is σ = 53143131102. Its totient is φ = 53143131100.

The previous prime is 53143131071. The next prime is 53143131109. The reversal of 53143131101 is 10113134135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47797327876 + 5345803225 = 218626^2 + 73115^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53143131101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53143131109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26571565550 + 26571565551.

It is an arithmetic number, because the mean of its divisors is an integer number (26571565551).

Almost surely, 253143131101 is an apocalyptic number.

It is an amenable number.

53143131101 is a deficient number, since it is larger than the sum of its proper divisors (1).

53143131101 is an equidigital number, since it uses as much as digits as its factorization.

53143131101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 53143131101 its reverse (10113134135), we get a palindrome (63256265236).

The spelling of 53143131101 in words is "fifty-three billion, one hundred forty-three million, one hundred thirty-one thousand, one hundred one".