Base | Representation |
---|---|
bin | 110001011111100100… |
… | …111101010000010001 |
3 | 12002011122011202222210 |
4 | 301133210331100101 |
5 | 1332314120144103 |
6 | 40225201422333 |
7 | 3560636106300 |
oct | 613744752021 |
9 | 162148152883 |
10 | 53143131153 |
11 | 205a0a04002 |
12 | a37163a9a9 |
13 | 501bcb9848 |
14 | 2801d54437 |
15 | 15b07ace03 |
hex | c5f93d411 |
53143131153 has 48 divisors (see below), whose sum is σ = 84519680256. Its totient is φ = 29599143840.
The previous prime is 53143131109. The next prime is 53143131211. The reversal of 53143131153 is 35113134135.
53143131153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53143131153 - 214 = 53143114769 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53143131153.
It is not an unprimeable number, because it can be changed into a prime (53143131653) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3095050 + ... + 3112172.
It is an arithmetic number, because the mean of its divisors is an integer number (1760826672).
Almost surely, 253143131153 is an apocalyptic number.
It is an amenable number.
53143131153 is a deficient number, since it is larger than the sum of its proper divisors (31376549103).
53143131153 is a wasteful number, since it uses less digits than its factorization.
53143131153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17674 (or 17667 counting only the distinct ones).
The product of its digits is 8100, while the sum is 30.
Adding to 53143131153 its reverse (35113134135), we get a palindrome (88256265288).
The spelling of 53143131153 in words is "fifty-three billion, one hundred forty-three million, one hundred thirty-one thousand, one hundred fifty-three".
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