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53143843 is a prime number
BaseRepresentation
bin1100101010111…
…0100100100011
310200222222122111
43022232210203
5102101100333
65135020151
71213500214
oct312564443
9120888574
1053143843
1127aa8835
121596a657
13b01937c
1470b540b
1549eb4cd
hex32ae923

53143843 has 2 divisors, whose sum is σ = 53143844. Its totient is φ = 53143842.

The previous prime is 53143841. The next prime is 53143873. The reversal of 53143843 is 34834135.

53143843 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 53143843 - 21 = 53143841 is a prime.

Together with 53143841, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (53143841) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26571921 + 26571922.

It is an arithmetic number, because the mean of its divisors is an integer number (26571922).

Almost surely, 253143843 is an apocalyptic number.

53143843 is a deficient number, since it is larger than the sum of its proper divisors (1).

53143843 is an equidigital number, since it uses as much as digits as its factorization.

53143843 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 17280, while the sum is 31.

The square root of 53143843 is about 7289.9823730925. The cubic root of 53143843 is about 375.9680894716.

Adding to 53143843 its reverse (34834135), we get a palindrome (87977978).

The spelling of 53143843 in words is "fifty-three million, one hundred forty-three thousand, eight hundred forty-three".