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53144046150973 is a prime number
BaseRepresentation
bin11000001010101100011111…
…11111100010010100111101
320222011112001221200012000121
430011112033333202110331
523431203001303312343
6305010012053454541
714123350001645101
oct1405261777422475
9228145057605017
1053144046150973
1115a2a299654028
125b63809641451
132386601174a2b
14d1a285257901
156225ea414aed
hex30558ffe253d

53144046150973 has 2 divisors, whose sum is σ = 53144046150974. Its totient is φ = 53144046150972.

The previous prime is 53144046150919. The next prime is 53144046150983. The reversal of 53144046150973 is 37905164044135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 52309605921444 + 834440229529 = 7232538^2 + 913477^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53144046150973 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 53144046150973.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53144046150983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26572023075486 + 26572023075487.

It is an arithmetic number, because the mean of its divisors is an integer number (26572023075487).

Almost surely, 253144046150973 is an apocalyptic number.

It is an amenable number.

53144046150973 is a deficient number, since it is larger than the sum of its proper divisors (1).

53144046150973 is an equidigital number, since it uses as much as digits as its factorization.

53144046150973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5443200, while the sum is 52.

The spelling of 53144046150973 in words is "fifty-three trillion, one hundred forty-four billion, forty-six million, one hundred fifty thousand, nine hundred seventy-three".