Base | Representation |
---|---|
bin | 100110101010101110001… |
… | …1010111110011010100100 |
3 | 200211001110102110012022120 |
4 | 1031111130122332122210 |
5 | 1144032420312323140 |
6 | 15145225130025540 |
7 | 1055645260121253 |
oct | 115253432763244 |
9 | 20731412405276 |
10 | 5314425120420 |
11 | 1769920485289 |
12 | 719b7a2782b0 |
13 | 2c71c05ca290 |
14 | 14531062479a |
15 | 933914da1d0 |
hex | 4d55c6be6a4 |
5314425120420 has 48 divisors (see below), whose sum is σ = 16025035750080. Its totient is φ = 1308166183296.
The previous prime is 5314425120373. The next prime is 5314425120421. The reversal of 5314425120420 is 240215244135.
It is a super-3 number, since 3×53144251204203 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (5314425120421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3406681990 + ... + 3406683549.
It is an arithmetic number, because the mean of its divisors is an integer number (333854911460).
Almost surely, 25314425120420 is an apocalyptic number.
It is an amenable number.
5314425120420 is an abundant number, since it is smaller than the sum of its proper divisors (10710610629660).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5314425120420 is a wasteful number, since it uses less digits than its factorization.
5314425120420 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6813365564 (or 6813365562 counting only the distinct ones).
The product of its (nonzero) digits is 38400, while the sum is 33.
The spelling of 5314425120420 in words is "five trillion, three hundred fourteen billion, four hundred twenty-five million, one hundred twenty thousand, four hundred twenty".
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