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5314442444134 = 22657221222067
BaseRepresentation
bin100110101010101110101…
…1101000011110101100110
3200211001111122001022222121
41031111131131003311212
51144032434231203014
615145230545220154
71055645560302565
oct115253535036546
920731448038877
105314442444134
11176992a2378aa
12719b8403165a
132c71c40844b5
14145312a53bdc
1593392cad124
hex4d55d743d66

5314442444134 has 4 divisors (see below), whose sum is σ = 7971663666204. Its totient is φ = 2657221222066.

The previous prime is 5314442444111. The next prime is 5314442444153. The reversal of 5314442444134 is 4314442444135.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×53144424441342 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1328610611032 + ... + 1328610611035.

It is an arithmetic number, because the mean of its divisors is an integer number (1992915916551).

Almost surely, 25314442444134 is an apocalyptic number.

5314442444134 is a deficient number, since it is larger than the sum of its proper divisors (2657221222070).

5314442444134 is a wasteful number, since it uses less digits than its factorization.

5314442444134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2657221222069.

The product of its digits is 1474560, while the sum is 43.

Adding to 5314442444134 its reverse (4314442444135), we get a palindrome (9628884888269).

Subtracting from 5314442444134 its reverse (4314442444135), we obtain a palindrome (999999999999).

The spelling of 5314442444134 in words is "five trillion, three hundred fourteen billion, four hundred forty-two million, four hundred forty-four thousand, one hundred thirty-four".

Divisors: 1 2 2657221222067 5314442444134