Base | Representation |
---|---|
bin | 1100101010111… |
… | …1011110010001 |
3 | 10201000011201022 |
4 | 3022233132101 |
5 | 102101210122 |
6 | 5135045225 |
7 | 1213514042 |
oct | 312573621 |
9 | 121004638 |
10 | 53147537 |
11 | 28000593 |
12 | 15970815 |
13 | b01ac61 |
14 | 70b68c9 |
15 | 49ec642 |
hex | 32af791 |
53147537 has 2 divisors, whose sum is σ = 53147538. Its totient is φ = 53147536.
The previous prime is 53147477. The next prime is 53147539. The reversal of 53147537 is 73574135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51394561 + 1752976 = 7169^2 + 1324^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53147537 is a prime.
Together with 53147539, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 53147497 and 53147506.
It is not a weakly prime, because it can be changed into another prime (53147539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26573768 + 26573769.
It is an arithmetic number, because the mean of its divisors is an integer number (26573769).
Almost surely, 253147537 is an apocalyptic number.
It is an amenable number.
53147537 is a deficient number, since it is larger than the sum of its proper divisors (1).
53147537 is an equidigital number, since it uses as much as digits as its factorization.
53147537 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 44100, while the sum is 35.
The square root of 53147537 is about 7290.2357300707. The cubic root of 53147537 is about 375.9768003831.
The spelling of 53147537 in words is "fifty-three million, one hundred forty-seven thousand, five hundred thirty-seven".
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