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53150333 is a prime number
BaseRepresentation
bin1100101011000…
…0001001111101
310201000022112212
43022300021331
5102101302313
65135110205
71213525145
oct312601175
9121008485
1053150333
11280026a5
1215972365
13b01c302
1470b7925
1549ed3a8
hex32b027d

53150333 has 2 divisors, whose sum is σ = 53150334. Its totient is φ = 53150332.

The previous prime is 53150323. The next prime is 53150371. The reversal of 53150333 is 33305135.

53150333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 50951044 + 2199289 = 7138^2 + 1483^2 .

It is a cyclic number.

It is not a de Polignac number, because 53150333 - 210 = 53149309 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53150299 and 53150308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53150323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26575166 + 26575167.

It is an arithmetic number, because the mean of its divisors is an integer number (26575167).

Almost surely, 253150333 is an apocalyptic number.

It is an amenable number.

53150333 is a deficient number, since it is larger than the sum of its proper divisors (1).

53150333 is an equidigital number, since it uses as much as digits as its factorization.

53150333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2025, while the sum is 23.

The square root of 53150333 is about 7290.4274908952. The cubic root of 53150333 is about 375.9833934306.

Adding to 53150333 its reverse (33305135), we get a palindrome (86455468).

The spelling of 53150333 in words is "fifty-three million, one hundred fifty thousand, three hundred thirty-three".