Base | Representation |
---|---|
bin | 111100011011011010110110… |
… | …1111111111100111111011000 |
3 | 2120201000011110020210020002012 |
4 | 1320312311231333330333120 |
5 | 1024132123330430220004 |
6 | 5122251222305325052 |
7 | 216650033555124356 |
oct | 17066655577747730 |
9 | 2521004406706065 |
10 | 531534113132504 |
11 | 1443aa3958855a9 |
12 | 4b746a57036788 |
13 | 19a785b4794131 |
14 | 95385618807d6 |
15 | 416b64e81b46e |
hex | 1e36d6dffcfd8 |
531534113132504 has 32 divisors (see below), whose sum is σ = 1045767868992000. Its totient is φ = 252791788547232.
The previous prime is 531534113132459. The next prime is 531534113132537. The reversal of 531534113132504 is 405231311435135.
It is a super-2 number, since 2×5315341131325042 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8069163584 + ... + 8069229455.
It is an arithmetic number, because the mean of its divisors is an integer number (32680245906000).
Almost surely, 2531534113132504 is an apocalyptic number.
It is an amenable number.
531534113132504 is a deficient number, since it is larger than the sum of its proper divisors (514233755859496).
531534113132504 is a wasteful number, since it uses less digits than its factorization.
531534113132504 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16138393247 (or 16138393243 counting only the distinct ones).
The product of its (nonzero) digits is 324000, while the sum is 41.
Adding to 531534113132504 its reverse (405231311435135), we get a palindrome (936765424567639).
The spelling of 531534113132504 in words is "five hundred thirty-one trillion, five hundred thirty-four billion, one hundred thirteen million, one hundred thirty-two thousand, five hundred four".
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