Base | Representation |
---|---|
bin | 1111011110000100101… |
… | …00110001010110100101 |
3 | 1212211000000112210202211 |
4 | 13233002110301112211 |
5 | 32202044021433331 |
6 | 1044104152403421 |
7 | 53255041446442 |
oct | 7570224612645 |
9 | 1784000483684 |
10 | 531541202341 |
11 | 195475173676 |
12 | 870240a6571 |
13 | 3b17c900006 |
14 | 1ba262189c9 |
15 | dc5ebe48b1 |
hex | 7bc25315a5 |
531541202341 has 2 divisors, whose sum is σ = 531541202342. Its totient is φ = 531541202340.
The previous prime is 531541202323. The next prime is 531541202347. The reversal of 531541202341 is 143202145135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 495997641441 + 35543560900 = 704271^2 + 188530^2 .
It is a cyclic number.
It is not a de Polignac number, because 531541202341 - 221 = 531539105189 is a prime.
It is a super-2 number, since 2×5315412023412 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (531541202347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265770601170 + 265770601171.
It is an arithmetic number, because the mean of its divisors is an integer number (265770601171).
Almost surely, 2531541202341 is an apocalyptic number.
It is an amenable number.
531541202341 is a deficient number, since it is larger than the sum of its proper divisors (1).
531541202341 is an equidigital number, since it uses as much as digits as its factorization.
531541202341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 531541202341 its reverse (143202145135), we get a palindrome (674743347476).
The spelling of 531541202341 in words is "five hundred thirty-one billion, five hundred forty-one million, two hundred two thousand, three hundred forty-one".
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