Base | Representation |
---|---|
bin | 100110101011100100111… |
… | …0110000000100110111101 |
3 | 200211020012100211200011201 |
4 | 1031113021312000212331 |
5 | 1144100200244030322 |
6 | 15150131225415501 |
7 | 1056041621154643 |
oct | 115271166004675 |
9 | 20736170750151 |
10 | 5316260923837 |
11 | 176a682773596 |
12 | 71a3b103a591 |
13 | 2c7423a449a6 |
14 | 14544637b193 |
15 | 9344c766d27 |
hex | 4d5c9d809bd |
5316260923837 has 2 divisors, whose sum is σ = 5316260923838. Its totient is φ = 5316260923836.
The previous prime is 5316260923801. The next prime is 5316260923847. The reversal of 5316260923837 is 7383290626135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4780406179396 + 535854744441 = 2186414^2 + 732021^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5316260923837 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5316260923847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2658130461918 + 2658130461919.
It is an arithmetic number, because the mean of its divisors is an integer number (2658130461919).
Almost surely, 25316260923837 is an apocalyptic number.
It is an amenable number.
5316260923837 is a deficient number, since it is larger than the sum of its proper divisors (1).
5316260923837 is an equidigital number, since it uses as much as digits as its factorization.
5316260923837 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9797760, while the sum is 55.
The spelling of 5316260923837 in words is "five trillion, three hundred sixteen billion, two hundred sixty million, nine hundred twenty-three thousand, eight hundred thirty-seven".
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