Base | Representation |
---|---|
bin | 100110101011100110101… |
… | …1011100101010101010111 |
3 | 200211020100120002012112112 |
4 | 1031113031123211111113 |
5 | 1144100311200331424 |
6 | 15150141215341235 |
7 | 1056043251535634 |
oct | 115271533452527 |
9 | 20736316065475 |
10 | 5316321105239 |
11 | 176a703738791 |
12 | 71a40922181b |
13 | 2c74333563a1 |
14 | 14545036518b |
15 | 93452ba360e |
hex | 4d5cd6e5557 |
5316321105239 has 2 divisors, whose sum is σ = 5316321105240. Its totient is φ = 5316321105238.
The previous prime is 5316321105203. The next prime is 5316321105257. The reversal of 5316321105239 is 9325011236135.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5316321105239 is a prime.
It is a super-3 number, since 3×53163211052393 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5316321105196 and 5316321105205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5316321105439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2658160552619 + 2658160552620.
It is an arithmetic number, because the mean of its divisors is an integer number (2658160552620).
Almost surely, 25316321105239 is an apocalyptic number.
5316321105239 is a deficient number, since it is larger than the sum of its proper divisors (1).
5316321105239 is an equidigital number, since it uses as much as digits as its factorization.
5316321105239 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 145800, while the sum is 41.
The spelling of 5316321105239 in words is "five trillion, three hundred sixteen billion, three hundred twenty-one million, one hundred five thousand, two hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.173 sec. • engine limits •