Base | Representation |
---|---|
bin | 1001111010001011… |
… | …01110101011101001 |
3 | 111201202021212121102 |
4 | 10331011232223221 |
5 | 41343342120101 |
6 | 2235515251145 |
7 | 245555141324 |
oct | 47505565351 |
9 | 14652255542 |
10 | 5319879401 |
11 | 228aa2a151 |
12 | 1045749ab5 |
13 | 66a1c9c45 |
14 | 38676b7bb |
15 | 21209086b |
hex | 13d16eae9 |
5319879401 has 2 divisors, whose sum is σ = 5319879402. Its totient is φ = 5319879400.
The previous prime is 5319879391. The next prime is 5319879443. The reversal of 5319879401 is 1049789135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4813584400 + 506295001 = 69380^2 + 22501^2 .
It is a cyclic number.
It is not a de Polignac number, because 5319879401 - 218 = 5319617257 is a prime.
It is a super-3 number, since 3×53198794013 (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (5319872401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2659939700 + 2659939701.
It is an arithmetic number, because the mean of its divisors is an integer number (2659939701).
Almost surely, 25319879401 is an apocalyptic number.
It is an amenable number.
5319879401 is a deficient number, since it is larger than the sum of its proper divisors (1).
5319879401 is an equidigital number, since it uses as much as digits as its factorization.
5319879401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 272160, while the sum is 47.
The square root of 5319879401 is about 72937.5033916023. The cubic root of 5319879401 is about 1745.6905558269.
The spelling of 5319879401 in words is "five billion, three hundred nineteen million, eight hundred seventy-nine thousand, four hundred one".
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