Base | Representation |
---|---|
bin | 110001100011000010… |
… | …001000010000100011 |
3 | 12002022200021102002101 |
4 | 301203002020100203 |
5 | 1332423441010201 |
6 | 40235032231231 |
7 | 3562241655055 |
oct | 614302102043 |
9 | 162280242071 |
10 | 53201110051 |
11 | 20620704451 |
12 | a388b3b517 |
13 | 502b00989b |
14 | 28099278d5 |
15 | 15b5911d01 |
hex | c63088423 |
53201110051 has 2 divisors, whose sum is σ = 53201110052. Its totient is φ = 53201110050.
The previous prime is 53201110033. The next prime is 53201110069. The reversal of 53201110051 is 15001110235.
It is a balanced prime because it is at equal distance from previous prime (53201110033) and next prime (53201110069).
It is a cyclic number.
It is not a de Polignac number, because 53201110051 - 25 = 53201110019 is a prime.
It is a super-2 number, since 2×532011100512 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53201110021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26600555025 + 26600555026.
It is an arithmetic number, because the mean of its divisors is an integer number (26600555026).
Almost surely, 253201110051 is an apocalyptic number.
53201110051 is a deficient number, since it is larger than the sum of its proper divisors (1).
53201110051 is an equidigital number, since it uses as much as digits as its factorization.
53201110051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 150, while the sum is 19.
Adding to 53201110051 its reverse (15001110235), we get a palindrome (68202220286).
The spelling of 53201110051 in words is "fifty-three billion, two hundred one million, one hundred ten thousand, fifty-one".
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