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5320123000063 = 1371433220312301
BaseRepresentation
bin100110101101011000000…
…0010101010010011111111
3200211121011112000110202221
41031122300002222103333
51144131102442000223
615152010351230211
71056236415236254
oct115326002522377
920747145013687
105320123000063
111771284813623
1271b0aa518367
132c78bac050b1
141456d126b42b
15935c6845b5d
hex4d6b00aa4ff

5320123000063 has 16 divisors (see below), whose sum is σ = 5365566114336. Its totient is φ = 5274780019200.

The previous prime is 5320123000061. The next prime is 5320123000067. The reversal of 5320123000063 is 3600003210235.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 5320123000063 - 21 = 5320123000061 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5320123000061) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 432489013 + ... + 432501313.

It is an arithmetic number, because the mean of its divisors is an integer number (335347882146).

Almost surely, 25320123000063 is an apocalyptic number.

5320123000063 is a deficient number, since it is larger than the sum of its proper divisors (45443114273).

5320123000063 is a wasteful number, since it uses less digits than its factorization.

5320123000063 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16074.

The product of its (nonzero) digits is 3240, while the sum is 25.

Adding to 5320123000063 its reverse (3600003210235), we get a palindrome (8920126210298).

The spelling of 5320123000063 in words is "five trillion, three hundred twenty billion, one hundred twenty-three million, sixty-three", and thus it is an aban number.

Divisors: 1 137 1433 2203 12301 196321 301811 1685237 3156899 17627333 27099103 432495163 2414944621 3712577111 38833014599 5320123000063