Base | Representation |
---|---|
bin | 100110101101011000000… |
… | …0010101010010011111111 |
3 | 200211121011112000110202221 |
4 | 1031122300002222103333 |
5 | 1144131102442000223 |
6 | 15152010351230211 |
7 | 1056236415236254 |
oct | 115326002522377 |
9 | 20747145013687 |
10 | 5320123000063 |
11 | 1771284813623 |
12 | 71b0aa518367 |
13 | 2c78bac050b1 |
14 | 1456d126b42b |
15 | 935c6845b5d |
hex | 4d6b00aa4ff |
5320123000063 has 16 divisors (see below), whose sum is σ = 5365566114336. Its totient is φ = 5274780019200.
The previous prime is 5320123000061. The next prime is 5320123000067. The reversal of 5320123000063 is 3600003210235.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 5320123000063 - 21 = 5320123000061 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5320123000061) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 432489013 + ... + 432501313.
It is an arithmetic number, because the mean of its divisors is an integer number (335347882146).
Almost surely, 25320123000063 is an apocalyptic number.
5320123000063 is a deficient number, since it is larger than the sum of its proper divisors (45443114273).
5320123000063 is a wasteful number, since it uses less digits than its factorization.
5320123000063 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16074.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 5320123000063 its reverse (3600003210235), we get a palindrome (8920126210298).
The spelling of 5320123000063 in words is "five trillion, three hundred twenty billion, one hundred twenty-three million, sixty-three", and thus it is an aban number.
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