Base | Representation |
---|---|
bin | 100110101101011000001… |
… | …1111011010101100010111 |
3 | 200211121012001012110020112 |
4 | 1031122300133122230113 |
5 | 1144131111404211023 |
6 | 15152011220553235 |
7 | 1056236536303442 |
oct | 115326037325427 |
9 | 20747161173215 |
10 | 5320130538263 |
11 | 1771288aa2142 |
12 | 71b0b0b5281b |
13 | 2c78bc644278 |
14 | 1456d2270659 |
15 | 935c7334478 |
hex | 4d6b07dab17 |
5320130538263 has 2 divisors, whose sum is σ = 5320130538264. Its totient is φ = 5320130538262.
The previous prime is 5320130538259. The next prime is 5320130538299. The reversal of 5320130538263 is 3628350310235.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5320130538263 - 22 = 5320130538259 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5320130538263.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5320130538253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2660065269131 + 2660065269132.
It is an arithmetic number, because the mean of its divisors is an integer number (2660065269132).
Almost surely, 25320130538263 is an apocalyptic number.
5320130538263 is a deficient number, since it is larger than the sum of its proper divisors (1).
5320130538263 is an equidigital number, since it uses as much as digits as its factorization.
5320130538263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 388800, while the sum is 41.
Adding to 5320130538263 its reverse (3628350310235), we get a palindrome (8948480848498).
The spelling of 5320130538263 in words is "five trillion, three hundred twenty billion, one hundred thirty million, five hundred thirty-eight thousand, two hundred sixty-three".
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