Base | Representation |
---|---|
bin | 110001100011000101… |
… | …101011010101001111 |
3 | 12002022202000122221020 |
4 | 301203011223111033 |
5 | 1332424210241033 |
6 | 40235104205223 |
7 | 3562252610520 |
oct | 614305532517 |
9 | 162282018836 |
10 | 53202040143 |
11 | 2062118a21a |
12 | a389309813 |
13 | 502b274035 |
14 | 2809aca847 |
15 | 15b5a476b3 |
hex | c6316b54f |
53202040143 has 16 divisors (see below), whose sum is σ = 81281458176. Its totient is φ = 30321784800.
The previous prime is 53202040093. The next prime is 53202040153. The reversal of 53202040143 is 34104020235.
It is not a de Polignac number, because 53202040143 - 210 = 53202039119 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53202040153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3299308 + ... + 3315393.
It is an arithmetic number, because the mean of its divisors is an integer number (5080091136).
Almost surely, 253202040143 is an apocalyptic number.
53202040143 is a deficient number, since it is larger than the sum of its proper divisors (28079418033).
53202040143 is a wasteful number, since it uses less digits than its factorization.
53202040143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6615094.
The product of its (nonzero) digits is 2880, while the sum is 24.
Adding to 53202040143 its reverse (34104020235), we get a palindrome (87306060378).
The spelling of 53202040143 in words is "fifty-three billion, two hundred two million, forty thousand, one hundred forty-three".
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