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5320514205053 is a prime number
BaseRepresentation
bin100110101101100011101…
…0110111111010101111101
3200211122011210010202010122
41031123013112333111331
51144132403114030203
615152113244144325
71056252205360505
oct115330726772575
920748153122118
105320514205053
111771465621733
1271b1995380a5
132c7950c87438
1414572b1c2a05
15935ead6d538
hex4d6c75bf57d

5320514205053 has 2 divisors, whose sum is σ = 5320514205054. Its totient is φ = 5320514205052.

The previous prime is 5320514204983. The next prime is 5320514205073. The reversal of 5320514205053 is 3505024150235.

5320514205053 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5315251863289 + 5262341764 = 2305483^2 + 72542^2 .

It is a cyclic number.

It is not a de Polignac number, because 5320514205053 - 214 = 5320514188669 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5320514205073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2660257102526 + 2660257102527.

It is an arithmetic number, because the mean of its divisors is an integer number (2660257102527).

Almost surely, 25320514205053 is an apocalyptic number.

It is an amenable number.

5320514205053 is a deficient number, since it is larger than the sum of its proper divisors (1).

5320514205053 is an equidigital number, since it uses as much as digits as its factorization.

5320514205053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90000, while the sum is 35.

Adding to 5320514205053 its reverse (3505024150235), we get a palindrome (8825538355288).

The spelling of 5320514205053 in words is "five trillion, three hundred twenty billion, five hundred fourteen million, two hundred five thousand, fifty-three".