Base | Representation |
---|---|
bin | 1111011111001000110… |
… | …10000101100100111001 |
3 | 1212212110212112012211121 |
4 | 13233210122011210321 |
5 | 32204231413134431 |
6 | 1044241020425241 |
7 | 53305154024104 |
oct | 7574432054471 |
9 | 1785425465747 |
10 | 532113021241 |
11 | 195738a2367a |
12 | 871636a8221 |
13 | 3b24120c7a9 |
14 | 1ba7c14773b |
15 | dc94ee7611 |
hex | 7be4685939 |
532113021241 has 2 divisors, whose sum is σ = 532113021242. Its totient is φ = 532113021240.
The previous prime is 532113021191. The next prime is 532113021277. The reversal of 532113021241 is 142120311235.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 434319222841 + 97793798400 = 659029^2 + 312720^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-532113021241 is a prime.
It is not a weakly prime, because it can be changed into another prime (532113021941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 266056510620 + 266056510621.
It is an arithmetic number, because the mean of its divisors is an integer number (266056510621).
Almost surely, 2532113021241 is an apocalyptic number.
It is an amenable number.
532113021241 is a deficient number, since it is larger than the sum of its proper divisors (1).
532113021241 is an equidigital number, since it uses as much as digits as its factorization.
532113021241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 532113021241 its reverse (142120311235), we get a palindrome (674233332476).
The spelling of 532113021241 in words is "five hundred thirty-two billion, one hundred thirteen million, twenty-one thousand, two hundred forty-one".
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