Base | Representation |
---|---|
bin | 100110101101110110001… |
… | …0000101000010000111101 |
3 | 200211200202221001202102002 |
4 | 1031123230100220100331 |
5 | 1144140140110412103 |
6 | 15152254521312045 |
7 | 1056303433504451 |
oct | 115335420502075 |
9 | 20750687052362 |
10 | 5321133294653 |
11 | 1771753028930 |
12 | 71b330935625 |
13 | 2c7a1c307c47 |
14 | 1457894d8661 |
15 | 936353ac488 |
hex | 4d6ec42843d |
5321133294653 has 24 divisors (see below), whose sum is σ = 6280001773920. Its totient is φ = 4458934681920.
The previous prime is 5321133294619. The next prime is 5321133294731. The reversal of 5321133294653 is 3564923311235.
It is a de Polignac number, because none of the positive numbers 2k-5321133294653 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5321133294598 and 5321133294607.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5321133294553) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9012626 + ... + 9584867.
It is an arithmetic number, because the mean of its divisors is an integer number (261666740580).
Almost surely, 25321133294653 is an apocalyptic number.
It is an amenable number.
5321133294653 is a deficient number, since it is larger than the sum of its proper divisors (958868479267).
5321133294653 is a wasteful number, since it uses less digits than its factorization.
5321133294653 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18597597 (or 18597560 counting only the distinct ones).
The product of its digits is 1749600, while the sum is 47.
The spelling of 5321133294653 in words is "five trillion, three hundred twenty-one billion, one hundred thirty-three million, two hundred ninety-four thousand, six hundred fifty-three".
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