Base | Representation |
---|---|
bin | 100110101101111110000… |
… | …1110110100001001011101 |
3 | 200211201110121021112012121 |
4 | 1031123330032310021131 |
5 | 1144141212210120433 |
6 | 15152341252502541 |
7 | 1056313166230462 |
oct | 115337416641135 |
9 | 20751417245177 |
10 | 5321401254493 |
11 | 1771880309045 |
12 | 71b3a661aa51 |
13 | 2c7a6299826c |
14 | 1457b2d2b669 |
15 | 9364db8cc2d |
hex | 4d6fc3b425d |
5321401254493 has 2 divisors, whose sum is σ = 5321401254494. Its totient is φ = 5321401254492.
The previous prime is 5321401254487. The next prime is 5321401254563. The reversal of 5321401254493 is 3944521041235.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4577319044089 + 744082210404 = 2139467^2 + 862602^2 .
It is a cyclic number.
It is not a de Polignac number, because 5321401254493 - 217 = 5321401123421 is a prime.
It is a super-2 number, since 2×53214012544932 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5321801254493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2660700627246 + 2660700627247.
It is an arithmetic number, because the mean of its divisors is an integer number (2660700627247).
Almost surely, 25321401254493 is an apocalyptic number.
It is an amenable number.
5321401254493 is a deficient number, since it is larger than the sum of its proper divisors (1).
5321401254493 is an equidigital number, since it uses as much as digits as its factorization.
5321401254493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 518400, while the sum is 43.
The spelling of 5321401254493 in words is "five trillion, three hundred twenty-one billion, four hundred one million, two hundred fifty-four thousand, four hundred ninety-three".
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