Base | Representation |
---|---|
bin | 100110101110011100110… |
… | …1111000101011011110011 |
3 | 200211211010111220221011211 |
4 | 1031130321233011123303 |
5 | 1144200320334432313 |
6 | 15153031513220551 |
7 | 1056350566044565 |
oct | 115347157053363 |
9 | 20754114827154 |
10 | 5322433124083 |
11 | 177225a819a29 |
12 | 71b634101757 |
13 | 2c7b986b339a |
14 | 14586ddb3335 |
15 | 936ae566e3d |
hex | 4d739bc56f3 |
5322433124083 has 2 divisors, whose sum is σ = 5322433124084. Its totient is φ = 5322433124082.
The previous prime is 5322433124081. The next prime is 5322433124117. The reversal of 5322433124083 is 3804213342235.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5322433124083 - 21 = 5322433124081 is a prime.
Together with 5322433124081, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (5322433124081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2661216562041 + 2661216562042.
It is an arithmetic number, because the mean of its divisors is an integer number (2661216562042).
Almost surely, 25322433124083 is an apocalyptic number.
5322433124083 is a deficient number, since it is larger than the sum of its proper divisors (1).
5322433124083 is an equidigital number, since it uses as much as digits as its factorization.
5322433124083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 414720, while the sum is 40.
The spelling of 5322433124083 in words is "five trillion, three hundred twenty-two billion, four hundred thirty-three million, one hundred twenty-four thousand, eighty-three".
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