Base | Representation |
---|---|
bin | 100110101110111000010… |
… | …0001110110000101111011 |
3 | 200211220111120201000000022 |
4 | 1031131300201312011323 |
5 | 1144204211203302001 |
6 | 15153303032401055 |
7 | 1056412430546204 |
oct | 115356041660573 |
9 | 20756446630008 |
10 | 5323352400251 |
11 | 17726917177a6 |
12 | 71b84bb4618b |
13 | 2c7cb3c98892 |
14 | 14591a10a5ab |
15 | 9371510011b |
hex | 4d77087617b |
5323352400251 has 2 divisors, whose sum is σ = 5323352400252. Its totient is φ = 5323352400250.
The previous prime is 5323352400229. The next prime is 5323352400253. The reversal of 5323352400251 is 1520042533235.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5323352400251 is a prime.
Together with 5323352400253, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (5323352400253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2661676200125 + 2661676200126.
It is an arithmetic number, because the mean of its divisors is an integer number (2661676200126).
Almost surely, 25323352400251 is an apocalyptic number.
5323352400251 is a deficient number, since it is larger than the sum of its proper divisors (1).
5323352400251 is an equidigital number, since it uses as much as digits as its factorization.
5323352400251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108000, while the sum is 35.
Adding to 5323352400251 its reverse (1520042533235), we get a palindrome (6843394933486).
The spelling of 5323352400251 in words is "five trillion, three hundred twenty-three billion, three hundred fifty-two million, four hundred thousand, two hundred fifty-one".
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