Base | Representation |
---|---|
bin | 100110101110111010101… |
… | …0110111010010111000111 |
3 | 200211220201020011020112022 |
4 | 1031131311112322113013 |
5 | 1144204342423421411 |
6 | 15153315045113355 |
7 | 1056414433321103 |
oct | 115356526722707 |
9 | 20756636136468 |
10 | 5323433420231 |
11 | 1772723425263 |
12 | 71b8730b885b |
13 | 2c7cc79c52b4 |
14 | 145926b9a903 |
15 | 9371c2a5edb |
hex | 4d7755ba5c7 |
5323433420231 has 2 divisors, whose sum is σ = 5323433420232. Its totient is φ = 5323433420230.
The previous prime is 5323433420219. The next prime is 5323433420237. The reversal of 5323433420231 is 1320243343235.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5323433420231 - 26 = 5323433420167 is a prime.
It is a super-2 number, since 2×53234334202312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5323433420191 and 5323433420200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5323433420237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2661716710115 + 2661716710116.
It is an arithmetic number, because the mean of its divisors is an integer number (2661716710116).
Almost surely, 25323433420231 is an apocalyptic number.
5323433420231 is a deficient number, since it is larger than the sum of its proper divisors (1).
5323433420231 is an equidigital number, since it uses as much as digits as its factorization.
5323433420231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 35.
Adding to 5323433420231 its reverse (1320243343235), we get a palindrome (6643676763466).
The spelling of 5323433420231 in words is "five trillion, three hundred twenty-three billion, four hundred thirty-three million, four hundred twenty thousand, two hundred thirty-one".
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