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5323433420231 is a prime number
BaseRepresentation
bin100110101110111010101…
…0110111010010111000111
3200211220201020011020112022
41031131311112322113013
51144204342423421411
615153315045113355
71056414433321103
oct115356526722707
920756636136468
105323433420231
111772723425263
1271b8730b885b
132c7cc79c52b4
14145926b9a903
159371c2a5edb
hex4d7755ba5c7

5323433420231 has 2 divisors, whose sum is σ = 5323433420232. Its totient is φ = 5323433420230.

The previous prime is 5323433420219. The next prime is 5323433420237. The reversal of 5323433420231 is 1320243343235.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5323433420231 - 26 = 5323433420167 is a prime.

It is a super-2 number, since 2×53234334202312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5323433420191 and 5323433420200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5323433420237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2661716710115 + 2661716710116.

It is an arithmetic number, because the mean of its divisors is an integer number (2661716710116).

Almost surely, 25323433420231 is an apocalyptic number.

5323433420231 is a deficient number, since it is larger than the sum of its proper divisors (1).

5323433420231 is an equidigital number, since it uses as much as digits as its factorization.

5323433420231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 155520, while the sum is 35.

Adding to 5323433420231 its reverse (1320243343235), we get a palindrome (6643676763466).

The spelling of 5323433420231 in words is "five trillion, three hundred twenty-three billion, four hundred thirty-three million, four hundred twenty thousand, two hundred thirty-one".