Base | Representation |
---|---|
bin | 100110101111010000001… |
… | …0000110110011000000011 |
3 | 200211222120101122110011102 |
4 | 1031132200100312120003 |
5 | 1144212331213020311 |
6 | 15153514321405015 |
7 | 1056441323636045 |
oct | 115364020663003 |
9 | 20758511573142 |
10 | 5324153251331 |
11 | 1772a62789aa2 |
12 | 71ba3419976b |
13 | 2c80b0b88c65 |
14 | 145994617a95 |
15 | 9376059443b |
hex | 4d7a0436603 |
5324153251331 has 2 divisors, whose sum is σ = 5324153251332. Its totient is φ = 5324153251330.
The previous prime is 5324153251297. The next prime is 5324153251349. The reversal of 5324153251331 is 1331523514235.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5324153251331 is a prime.
It is a super-2 number, since 2×53241532513312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5324123251331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2662076625665 + 2662076625666.
It is an arithmetic number, because the mean of its divisors is an integer number (2662076625666).
Almost surely, 25324153251331 is an apocalyptic number.
5324153251331 is a deficient number, since it is larger than the sum of its proper divisors (1).
5324153251331 is an equidigital number, since it uses as much as digits as its factorization.
5324153251331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 162000, while the sum is 38.
Adding to 5324153251331 its reverse (1331523514235), we get a palindrome (6655676765566).
The spelling of 5324153251331 in words is "five trillion, three hundred twenty-four billion, one hundred fifty-three million, two hundred fifty-one thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •