Base | Representation |
---|---|
bin | 1001111010101110… |
… | …10111110101111011 |
3 | 111202001222211222021 |
4 | 10331113113311323 |
5 | 41401033120233 |
6 | 2240202335311 |
7 | 245642353366 |
oct | 47527276573 |
9 | 14661884867 |
10 | 5324504443 |
11 | 22925a8aa5 |
12 | 10471ba537 |
13 | 66b15915b |
14 | 3872130dd |
15 | 2126a5e2d |
hex | 13d5d7d7b |
5324504443 has 2 divisors, whose sum is σ = 5324504444. Its totient is φ = 5324504442.
The previous prime is 5324504357. The next prime is 5324504447. The reversal of 5324504443 is 3444054235.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5324504443 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5324504399 and 5324504408.
It is not a weakly prime, because it can be changed into another prime (5324504447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2662252221 + 2662252222.
It is an arithmetic number, because the mean of its divisors is an integer number (2662252222).
Almost surely, 25324504443 is an apocalyptic number.
5324504443 is a deficient number, since it is larger than the sum of its proper divisors (1).
5324504443 is an equidigital number, since it uses as much as digits as its factorization.
5324504443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 115200, while the sum is 34.
The square root of 5324504443 is about 72969.2020170154. The cubic root of 5324504443 is about 1746.1963037256.
Adding to 5324504443 its reverse (3444054235), we get a palindrome (8768558678).
The spelling of 5324504443 in words is "five billion, three hundred twenty-four million, five hundred four thousand, four hundred forty-three".
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