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53254201436893 is a prime number
BaseRepresentation
bin11000001101111001101011…
…10000100110101011011101
320222120001101212021111122001
430012330311300212223131
523440004101031440033
6305132350431522301
714134326520302142
oct1406746560465335
9228501355244561
1053254201436893
1115a71a86416806
125b81030389391
132393b078a17a2
14d21734d003c9
156253e5e82e7d
hex306f35c26add

53254201436893 has 2 divisors, whose sum is σ = 53254201436894. Its totient is φ = 53254201436892.

The previous prime is 53254201436873. The next prime is 53254201436897. The reversal of 53254201436893 is 39863410245235.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 53250689452249 + 3511984644 = 7297307^2 + 59262^2 .

It is a cyclic number.

It is not a de Polignac number, because 53254201436893 - 245 = 18069829348061 is a prime.

It is a super-2 number, since 2×532542014368932 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53254201436897) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26627100718446 + 26627100718447.

It is an arithmetic number, because the mean of its divisors is an integer number (26627100718447).

Almost surely, 253254201436893 is an apocalyptic number.

It is an amenable number.

53254201436893 is a deficient number, since it is larger than the sum of its proper divisors (1).

53254201436893 is an equidigital number, since it uses as much as digits as its factorization.

53254201436893 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18662400, while the sum is 55.

The spelling of 53254201436893 in words is "fifty-three trillion, two hundred fifty-four billion, two hundred one million, four hundred thirty-six thousand, eight hundred ninety-three".