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53280507800413 is a prime number
BaseRepresentation
bin11000001110101010101011…
…01111011010101101011101
320222122120022012100020022001
430013111111233122231131
523440421434444103123
6305152421040322301
714136250436556415
oct1407252557325535
9228576265306261
1053280507800413
1115a821556a7003
125b86152313391
13239643a96056a
14d22b0c983645
15625e356a10ad
hex307555bdab5d

53280507800413 has 2 divisors, whose sum is σ = 53280507800414. Its totient is φ = 53280507800412.

The previous prime is 53280507800257. The next prime is 53280507800467. The reversal of 53280507800413 is 31400870508235.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51478142479929 + 1802365320484 = 7174827^2 + 1342522^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53280507800413 is a prime.

It is a super-2 number, since 2×532805078004132 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53280507800473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26640253900206 + 26640253900207.

It is an arithmetic number, because the mean of its divisors is an integer number (26640253900207).

Almost surely, 253280507800413 is an apocalyptic number.

It is an amenable number.

53280507800413 is a deficient number, since it is larger than the sum of its proper divisors (1).

53280507800413 is an equidigital number, since it uses as much as digits as its factorization.

53280507800413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 806400, while the sum is 46.

The spelling of 53280507800413 in words is "fifty-three trillion, two hundred eighty billion, five hundred seven million, eight hundred thousand, four hundred thirteen".