Base | Representation |
---|---|
bin | 1111100000101010000… |
… | …10101110010110100111 |
3 | 1212221120201220020100212 |
4 | 13300111002232112213 |
5 | 32212414304333031 |
6 | 1044454005330035 |
7 | 53334322406543 |
oct | 7602502562647 |
9 | 1787521806325 |
10 | 532928980391 |
11 | 196017574885 |
12 | 87350a0691b |
13 | 3b34128c762 |
14 | 1bb18668a23 |
15 | dce197312b |
hex | 7c150ae5a7 |
532928980391 has 2 divisors, whose sum is σ = 532928980392. Its totient is φ = 532928980390.
The previous prime is 532928980253. The next prime is 532928980399. The reversal of 532928980391 is 193089829235.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 532928980391 - 210 = 532928979367 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 532928980391.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (532928980399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 266464490195 + 266464490196.
It is an arithmetic number, because the mean of its divisors is an integer number (266464490196).
Almost surely, 2532928980391 is an apocalyptic number.
532928980391 is a deficient number, since it is larger than the sum of its proper divisors (1).
532928980391 is an equidigital number, since it uses as much as digits as its factorization.
532928980391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8398080, while the sum is 59.
The spelling of 532928980391 in words is "five hundred thirty-two billion, nine hundred twenty-eight million, nine hundred eighty thousand, three hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •